EuroBillTracker

Posted: **Thu Oct 27, 2005 9:03 pm**

golfinha wrote:
androl wrote:120 = 4!*(4+4/4)

we already had 120

right, but sometimes I find shorter solutions

Posted: **Fri Oct 28, 2005 12:55 pm**

127 = (4^4 - sqrt4) / sqrt4

Posted: **Tue Nov 08, 2005 4:09 pm**

128 = 4 x 4 x (4 + 4)
129 = (4^4 + sqrt4) / sqrt4

Posted: **Wed Nov 09, 2005 1:06 am**

130 = 4^4/sqrt(4) + sqrt(4)
130 = (4^4+4)/sqrt(4)

Posted: **Wed Nov 09, 2005 1:18 am**

131 = ?

132 = 44 * ld(4+4)

Posted: **Mon Nov 14, 2005 1:44 pm**

131 and 133 = ? (can be done with 5 4s)

134 = 44 / .4 + 4!

Posted: **Sat Jun 10, 2006 11:45 pm**

also read this
http://www.math.hmc.edu/funfacts/ffiles/10006.8.shtml
they say it's possible to get all numbers until 112 with only

the four arithmetic operations (+,x,-,/), concatenation (44 is ok and uses up two 4's), decimal points (using 4.4 is ok), powers (using 4^4 is ok), square roots, factorials (using 4! is ok), and overbars for indicating repeating digits (e.g., writing .4 with an overbar would be a way of expressing 4/9)

Posted: **Tue Jul 25, 2006 10:44 pm**

lazza wrote:134 = 44 / .4 + 4!

44 / 0,(4) = 99
99 + 24 = 123

Posted: **Wed Jul 26, 2006 12:42 am**

androl wrote:
and overbars for indicating repeating digits (e.g., writing .4 with an overbar would be a way of expressing 4/9)

Then I've got the long missing 107!

107 = (4! + 4!) / .4 overbar - ld(sqrt(4))

Posted: **Wed Jul 26, 2006 10:17 am**

Zé da Silva wrote:44 / 0,(4) = 99

no, 44 / 0,4overbar = 99

Posted: **Thu Aug 03, 2006 1:12 am**

well, the next one I know is
140=4!*ld(4+4)!-4

Posted: **Thu Aug 03, 2006 1:14 am**

141=?
142=4!*ld(4+4)!-SQRT4
143=4!*ld(4+4)!-ld(SQRT4)
144=(4+SQRT4)!-4!*4!=(4+SQRT4)!*,4/SQRT4
145=4!*ld(4+4)!+ld(SQRT4)
146=4!*ld(4+4)!+SQRT4
147=?
148=4!*ld(4+4)!+4

Posted: **Thu Aug 03, 2006 1:21 am**

35=!4*4-(4/4)
37=!4*4+(4/4)
107=4*4!+!4+√4
136=(4!+!4)4+4

Posted: **Thu Aug 03, 2006 1:28 am**

EDIT: Never mind...

EuroBillTracker

Game of 4 4's