Game of 4 4's

[golfinha]

ok, sorry

[Craft]

ok, sorry

Oh, don't worry, this is just a game
Your solution is right too (and simpler), there are many ways to form some of the numbers.

Now on to 25...

I found

25 = 4! + (sqrt4 + sqrt4)/4

but maybe there's a simpler way

Edit: Oh, lazza below found it first

[lazza]

4! + (4 / (sqrt4 x sqrt4)) = 25

[vermeer]

4! + ((4 + 4)/4)= 26

[lazza]

4! + (4- (4/4)) = 27

[vermeer]

44 - (4 x 4)= 28

[vermeer]

4! + 4 + 4/4= 29

[lazza]

4 x (4+4) - sqrt4 = 30

EDIT: 30 not 32!

[lazza]

can't seem to do 31 properly...

(4 x (4+4)) - cos4 = 31.002435

[golfinha]

32=4*4+4*4

[androl]

4!+4*sqrt(4)+i^4 = 33

[golfinha]

34 = 4!+4+4+SQRT(4)

[lazza]

35 = (((4-i^4)!)^sqrt4) - i^4 I think

[Craft]

35 = (((4-i^4)!)^sqrt4) - i^4 I think

Your calculation is correct, BUT:
the complex unit i is a number, not a mathematical operator or function, and so it can't be used (using it is the same as using any other number than 4).

You can of course use i if you write it with 4's, like sqrt(-4/4), but it takes two of the four available 4's.

Another thing:

can't seem to do 31 properly...

(4 x (4+4)) - cos4 = 31.002435

There is a possibility: you could use function Int or Fix, which truncate positive real numbers to the nearest smaller integer:

Int((4 x (4+4)) - cos4) = 31

But I'd consider using Int or Fix sort of cheating, so it's better not to use them here

I haven't found a way to calculate 31, either...

[golfinha]

36 = 4! + 4 x 4 - 4