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Game of 4 4's
Posted: Thu Aug 25, 2005 9:55 pm
by Craft
We played this at school many years ago. The task is to count up positive integer numbers 0, 1, 2, 3, ... by forming each of them by using exactly four 4's and using mathematical operators. Maybe this could be played here too... (but it might get tricky very quickly, because I don't remember if every integer can be formed this way very far).
I'll start with two numbers to show the principle, but please continue by only one at a time.
0 = 4-4+4-4
1 = 4/4+4-4
...
Posted: Thu Aug 25, 2005 10:07 pm
by alex77r
2 = 4/4+4/4
Posted: Thu Aug 25, 2005 10:24 pm
by jabosa2
3 =( 4 x 4 - 4) : 4 This is what you mean???
Posted: Thu Aug 25, 2005 10:44 pm
by de*lerger
4 = (4-4)x4+4
Posted: Thu Aug 25, 2005 10:46 pm
by Hugo & Any
5 = 4/4+4 right
Posted: Thu Aug 25, 2005 10:52 pm
by de*lerger
You need to use 4 times the 4
5 = (4x4+4):4 will do
Posted: Thu Aug 25, 2005 11:09 pm
by Hugo & Any
6 = 4+4/4+4
i think there is no need of parentesis
Posted: Thu Aug 25, 2005 11:24 pm
by Elmo
Hugo & Any wrote: 6 = 4+4/4+4
i think there is no need of parentesis
Probably you mean: (4+4)/4+4 = 6
44/4-4 =
7
8
Posted: Thu Aug 25, 2005 11:27 pm
by Fons
4+4+4-4 = 8
Posted: Thu Aug 25, 2005 11:40 pm
by vermeer
4+4+(4/4)=9
Posted: Fri Aug 26, 2005 12:00 am
by Elmo
(44-4)/4 = 10
Posted: Fri Aug 26, 2005 11:01 am
by noogie
44/4 is the only way to get to 11, but where do you leave the fourth 4....
Posted: Fri Aug 26, 2005 1:03 pm
by golfinha
12=(44+4)/4
Posted: Fri Aug 26, 2005 1:29 pm
by lazza
13 = 4 + 4 + 4 + (4/4)
...Using noogie's spare 4
Posted: Fri Aug 26, 2005 1:38 pm
by lazza
Um... or maybe ((SQRT 44) x 4 ) / SQRT 4 .... nearly