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androl
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by androl » Thu Oct 27, 2005 9:03 pm
golfinha wrote: androl wrote: 120 = 4!*(4+4/4)
we already had 120
right, but sometimes I find shorter solutions
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lazza
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by lazza » Fri Oct 28, 2005 12:55 pm
127 = (4^4 - sqrt4) / sqrt4
lazza
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by lazza » Tue Nov 08, 2005 4:09 pm
128 = 4 x 4 x (4 + 4)
129 = (4^4 + sqrt4) / sqrt4
micro
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by micro » Wed Nov 09, 2005 1:06 am
130 = 4^4/sqrt(4) + sqrt(4)
130 = (4^4+4)/sqrt(4)
micro
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by micro » Wed Nov 09, 2005 1:18 am
131 = ?
132 = 44 * ld(4+4)
lazza
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by lazza » Mon Nov 14, 2005 1:44 pm
131 and 133 = ? (can be done with 5 4s)
134 = 44 / .4 + 4!
androl
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by androl » Sat Jun 10, 2006 11:45 pm
also read this
http://www.math.hmc.edu/funfacts/ffiles/10006.8.shtml
they say it's possible to get all numbers until 112 with only
the four arithmetic operations (+,x,-,/), concatenation (44 is ok and uses up two 4's), decimal points (using 4.4 is ok), powers (using 4^4 is ok), square roots, factorials (using 4! is ok), and overbars for indicating repeating digits (e.g., writing .4 with an overbar would be a way of expressing 4/9)
Joshu, a Chinese Zen master, asked a cow:
"Do you have Buddha-nature or not?"
The cow answered: "Moo."
JP Simões
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by JP Simões » Tue Jul 25, 2006 10:44 pm
lazza wrote: 134 = 44 / .4 + 4!
44 / 0,(4) = 99
99 + 24 = 123
De férias por período indeterminado...
micro
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by micro » Wed Jul 26, 2006 12:42 am
androl wrote: and overbars for indicating repeating digits (e.g., writing .4 with an overbar would be a way of expressing 4/9)
Then I've got the long missing
107 !
107 = (4! + 4!) / .4 overbar - ld(sqrt(4))
androl
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by androl » Wed Jul 26, 2006 10:17 am
Zé da Silva wrote: 44 / 0,(4) = 99
no, 44 / 0,4overbar = 99
Joshu, a Chinese Zen master, asked a cow:
"Do you have Buddha-nature or not?"
The cow answered: "Moo."
golfinha
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by golfinha » Thu Aug 03, 2006 1:12 am
well, the next one I know is
140 =4!*ld(4+4)!-4
golfinha
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by golfinha » Thu Aug 03, 2006 1:14 am
141 =?
142 =4!*ld(4+4)!-SQRT4
143 =4!*ld(4+4)!-ld(SQRT4)
144 =(4+SQRT4)!-4!*4!=(4+SQRT4)!*,4/SQRT4
145 =4!*ld(4+4)!+ld(SQRT4)
146 =4!*ld(4+4)!+SQRT4
147 =?
148 =4!*ld(4+4)!+4
JP Simões
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by JP Simões » Thu Aug 03, 2006 1:21 am
35 =!4*4-(4/4)
37 =!4*4+(4/4)
107 =4*4!+!4+√4
136 =(4!+!4)4+4
Last edited by
JP Simões on Thu Aug 03, 2006 12:04 pm, edited 6 times in total.
De férias por período indeterminado...
JP Simões
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by JP Simões » Thu Aug 03, 2006 1:28 am
EDIT: Never mind...
De férias por período indeterminado...